Equation for circle is y^2 + x^2 = r^2
re arrage
y = (r^2 + x^2)^0.5
Differentiate using substitution
For example z=r^2 + x^2
so
=(z)^0.5How do you work out the gradient at one point of a circle?
x^2+y^2+ax +by +c=0
2x+2y*y麓+a+by麓= 0 so y麓= (-2x-a)/(2y+b)
No comments:
Post a Comment